In the last article, we had discussed the Drilling Machine, Surface Grinding Machine, Milling Machine, lathe machine, etc. Radial Drilling Machine: Definition, Diagram, Parts, Working, Advantages, Disadvantages, and Applications Drilling Machine is used to make circular holes on the components with the help of Drill bits. Gas turbines operate to the Brayton cycle as shown on the T S diagram in Fig. In this article, I will be explaining about Supercharger VS Turbocharger and… Thermal efficiency1 TLOW / THIGH or the ratio of the work produced (upper green shaded region) divided by the work that could have been ideally produced if the heat sink were at absolute zero (upper green shaded +lower gray shaded regions). Supercharger VS Turbocharger A supercharger is an air compressor used for forced induction of air into an internal combustion engine whereas Turbocharger works on the exhaust gases from the cylinder for better efficiency. In this article, we elaborate on the Draft Tube… In effect, it says that the energy into the control volume consisting of the entering enthalpy, kinetic energy, and potential energy plus any heat crossing the boundary equals the exiting enthalpy, kinetic energy, and potential energy plus the work output of the control volume.įig 2 simplifies Fig 1 for the case of reversible adiabatic turbines, compressors and pumps.Draft tube: Definition, Function, Types, Applications, Advantages, Disadvantages, and Efficiency If you had observed our previous articles, you can notice that there is a component called Draft Tube which is attached to the end of the Kaplan Turbine and Francis Turbine. Fig 1 is a generic control volume that can be simplified to represent the control volumes for the turbine, pump, condenser, and boiler of the Rankine cycle. So does $W$ in the efficiency really equal $W_$. However, this doesn't seem to exploit the $PV$ work that occurs when the water vapor expands (i.e., during the isobaric portions of the cycle) in any way. Looking at real-life implementations of the Rankine cycle, it looks like all the work is extracted in the turbine, and some additional work is required in the pump: My question is about what the work $W$ in $e = W/Q_h$ actually refers to. Or, since Dq Dw, we could just as well consider the difference between the heat added to the cycle in process 2-3, and the heat rejected by the cycle in process 4-1. Moreover, Schroeder calculates the efficiency by referring to tables of enthalpies (so that he never has to worry where the work happens in the cycle). For instance in this example, we would like to find the net work of the cycle and we could calculate this by taking the difference of the work done all the way around the cycle. Use item B 2 and find (A) mass of air required, lb/sec. The constant pressure heat extraction process simply cools the air to its original state. For the gas turbine operation the constant pressure heat addition process is an idealization of the combustion process. Air enters the compressor section at 15 psia, 500 degree Rankine. The Brayton cycle (or Joule cycle) represents the operation of a gas turbine engine. I know that efficiency $e = W/Q_h = 1 - Q_c/Q_h$, and the total $PV$ work done during the process is represented by the area enclosed by the cycle. >(BRAYTON CYCLE, AIR STANDARD) The turbine section of a Brayton Cycle gas turbine receives the hot compressed air at 150 psia, 2100 degree Rankine, expands it to 15 psia and develops a gross output of 15000 hp. I am trying to understand Schroeder's treatment of heat engines, and am having a very hard time understanding the Rankine cycle.
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